S.K.NEET
The Chart of
Volume and Surface Area
TYPE - 1
Question 1 :
How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Formulae used :
Distance Formula to find distance between two points (x1,y1) and (x2,y2) is : D = √[(x2 – x1)2 + (y2 – y1)2 ].
Solution :
Sol. (i) Here x1 = 2, y1 = 3, x2 = 4 and y2 = 1
∴ The required distance
Classwork Questions
( R S Agarwal )
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 1176
(ii) 5625
(iii) 9075
Answer
(i) 441
(ii) 576
(iii) 11025
Homework Questions
( R S Agarwal )
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025
CBSE Questions
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025
NCERT Questions
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025
Olympiad Questions
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025
MCQ Questions
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025
Fill in the blanks
Q.1. How many bricks will be required for a wall which is 8 m long, 6 m high and 22.5 cm thick if each brick measures 25 cm * 11.25 cm * 6 cm?
(i) 441
(ii) 576
(iii) 11025
Answer
(i) 441
(ii) 576
(iii) 11025